Base | Representation |
---|---|
bin | 10011000101010110111… |
… | …010111101111111010111 |
3 | 11122101000100100102222122 |
4 | 103011112322331333113 |
5 | 132441243332332434 |
6 | 2442243133050155 |
7 | 163514202221336 |
oct | 23052672757727 |
9 | 4571010312878 |
10 | 1311423324119 |
11 | 466198306727 |
12 | 1921b502695b |
13 | 9688893b81c |
14 | 4768a771d1d |
15 | 241a6c33c2e |
hex | 13156ebdfd7 |
1311423324119 has 2 divisors, whose sum is σ = 1311423324120. Its totient is φ = 1311423324118.
The previous prime is 1311423324023. The next prime is 1311423324137. The reversal of 1311423324119 is 9114233241131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311423324119 - 224 = 1311406546903 is a prime.
It is a super-2 number, since 2×13114233241192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311423321119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711662059 + 655711662060.
It is an arithmetic number, because the mean of its divisors is an integer number (655711662060).
Almost surely, 21311423324119 is an apocalyptic number.
1311423324119 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311423324119 is an equidigital number, since it uses as much as digits as its factorization.
1311423324119 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15552, while the sum is 35.
The spelling of 1311423324119 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, three hundred twenty-four thousand, one hundred nineteen".
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