Base | Representation |
---|---|
bin | 10011000101010110111… |
… | …110010011111000001000 |
3 | 11122101000101222221202002 |
4 | 103011112332103320020 |
5 | 132441244043401300 |
6 | 2442243203530132 |
7 | 163514212530452 |
oct | 23052676237010 |
9 | 4571011887662 |
10 | 1311424200200 |
11 | 466198854964 |
12 | 1921b5389948 |
13 | 96888b8750a |
14 | 4768a91d2d2 |
15 | 241a6d585d5 |
hex | 13156f93e08 |
1311424200200 has 48 divisors (see below), whose sum is σ = 3049252335360. Its totient is φ = 524536808000.
The previous prime is 1311424200181. The next prime is 1311424200209. The reversal of 1311424200200 is 20024241131.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is not an unprimeable number, because it can be changed into a prime (1311424200209) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3129065 + ... + 3523335.
It is an arithmetic number, because the mean of its divisors is an integer number (63526090320).
Almost surely, 21311424200200 is an apocalyptic number.
1311424200200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1311424200200 is an abundant number, since it is smaller than the sum of its proper divisors (1737828135160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311424200200 is a wasteful number, since it uses less digits than its factorization.
1311424200200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 410918 (or 410909 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1311424200200 its reverse (20024241131), we get a palindrome (1331448441331).
The spelling of 1311424200200 in words is "one trillion, three hundred eleven billion, four hundred twenty-four million, two hundred thousand, two hundred".
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