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131142422220973 is a prime number
BaseRepresentation
bin11101110100010111111001…
…011111011101000010101101
3122012100002111212222011111221
4131310113321133131002231
5114142114140042032343
61142525555210543341
736423504322312522
oct3564277137350255
9565302455864457
10131142422220973
1138871209516779
1212860343a37b51
1358238a61ab957
1424554817d9149
1510264ae4e65ed
hex7745f97dd0ad

131142422220973 has 2 divisors, whose sum is σ = 131142422220974. Its totient is φ = 131142422220972.

The previous prime is 131142422220967. The next prime is 131142422221091. The reversal of 131142422220973 is 379022224241131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 79353141009444 + 51789281211529 = 8908038^2 + 7196477^2 .

It is a cyclic number.

It is not a de Polignac number, because 131142422220973 - 221 = 131142420123821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131142422220673) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571211110486 + 65571211110487.

It is an arithmetic number, because the mean of its divisors is an integer number (65571211110487).

Almost surely, 2131142422220973 is an apocalyptic number.

It is an amenable number.

131142422220973 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142422220973 is an equidigital number, since it uses as much as digits as its factorization.

131142422220973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 290304, while the sum is 43.

The spelling of 131142422220973 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred twenty-two million, two hundred twenty thousand, nine hundred seventy-three".