131143113044202 has 128 divisors (see below), whose sum is σ = 318826112048640. Its totient is φ = 35105676410880.

The previous prime is 131143113044197. The next prime is 131143113044233. The reversal of 131143113044202 is 202440311341131.

It is a self number, because there is not a number n which added to its sum of digits gives 131143113044202.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1059620508 + ... + 1059744264.

It is an arithmetic number, because the mean of its divisors is an integer number (2490829000380).

Almost surely, 2^{131143113044202} is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131143113044202, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (159413056024320).

131143113044202 is an abundant number, since it is smaller than the sum of its proper divisors (187682999004438).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131143113044202 is a wasteful number, since it uses less digits than its factorization.

131143113044202 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130496.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 131143113044202 its reverse (202440311341131), we get a palindrome (333583424385333).

The spelling of 131143113044202 in words is "one hundred thirty-one trillion, one hundred forty-three billion, one hundred thirteen million, forty-four thousand, two hundred two".