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131144441550 = 2352874296277
BaseRepresentation
bin111101000100011010…
…0010101111011001110
3110112111200101220021220
41322020310111323032
54122040434112200
6140125200304210
712321611234433
oct1721064257316
9415450356256
10131144441550
1150688688aa1
1221500012066
13c4a0015895
1464c1495b8a
1536285774a0
hex1e88d15ece

131144441550 has 24 divisors (see below), whose sum is σ = 325238215416. Its totient is φ = 34971851040.

The previous prime is 131144441537. The next prime is 131144441599. The reversal of 131144441550 is 55144441131.

It is a super-2 number, since 2×1311444415502 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 437147989 + ... + 437148288.

It is an arithmetic number, because the mean of its divisors is an integer number (13551592309).

Almost surely, 2131144441550 is an apocalyptic number.

131144441550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131144441550 is an abundant number, since it is smaller than the sum of its proper divisors (194093773866).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131144441550 is a wasteful number, since it uses less digits than its factorization.

131144441550 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 874296292 (or 874296287 counting only the distinct ones).

The product of its (nonzero) digits is 19200, while the sum is 33.

Adding to 131144441550 its reverse (55144441131), we get a palindrome (186288882681).

The spelling of 131144441550 in words is "one hundred thirty-one billion, one hundred forty-four million, four hundred forty-one thousand, five hundred fifty".

Divisors: 1 2 3 5 6 10 15 25 30 50 75 150 874296277 1748592554 2622888831 4371481385 5245777662 8742962770 13114444155 21857406925 26228888310 43714813850 65572220775 131144441550