Base | Representation |
---|---|
bin | 11000011011011011… |
… | …11010000100110111 |
3 | 1020212000021001202021 |
4 | 30031231322010313 |
5 | 203324422240210 |
6 | 10005220454011 |
7 | 643001000245 |
oct | 141555720467 |
9 | 36760231667 |
10 | 13115040055 |
11 | 5620109787 |
12 | 266024a307 |
13 | 1310180140 |
14 | 8c5b53795 |
15 | 51b5c7bda |
hex | 30db7a137 |
13115040055 has 32 divisors (see below), whose sum is σ = 17065641600. Its totient is φ = 9618365952.
The previous prime is 13115040049. The next prime is 13115040109. The reversal of 13115040055 is 55004051131.
It is a happy number.
It is not a de Polignac number, because 13115040055 - 25 = 13115040023 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6462781 + ... + 6464809.
It is an arithmetic number, because the mean of its divisors is an integer number (533301300).
Almost surely, 213115040055 is an apocalyptic number.
13115040055 is a deficient number, since it is larger than the sum of its proper divisors (3950601545).
13115040055 is a wasteful number, since it uses less digits than its factorization.
13115040055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2683.
The product of its (nonzero) digits is 1500, while the sum is 25.
Adding to 13115040055 its reverse (55004051131), we get a palindrome (68119091186).
The spelling of 13115040055 in words is "thirteen billion, one hundred fifteen million, forty thousand, fifty-five".
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