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131153141055 = 3514939585283
BaseRepresentation
bin111101000100101010…
…1100001110100111111
3110112112021202212202210
41322021111201310333
54122100201003210
6140130110551503
712322045206426
oct1721125416477
9415467685683
10131153141055
1150692590072
1221502b08593
13c4a1a70511
1464c26bc2bd
1536291e4e20
hex1e89561d3f

131153141055 has 16 divisors (see below), whose sum is σ = 209859431040. Its totient is φ = 69943540128.

The previous prime is 131153141047. The next prime is 131153141057. The reversal of 131153141055 is 550141351131.

It is not a de Polignac number, because 131153141055 - 23 = 131153141047 is a prime.

It is a super-2 number, since 2×1311531410552 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131153141057) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 68557 + ... + 516726.

It is an arithmetic number, because the mean of its divisors is an integer number (13116214440).

Almost surely, 2131153141055 is an apocalyptic number.

131153141055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

131153141055 is a deficient number, since it is larger than the sum of its proper divisors (78706289985).

131153141055 is a wasteful number, since it uses less digits than its factorization.

131153141055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 600230.

The product of its (nonzero) digits is 4500, while the sum is 30.

Adding to 131153141055 its reverse (550141351131), we get a palindrome (681294492186).

The spelling of 131153141055 in words is "one hundred thirty-one billion, one hundred fifty-three million, one hundred forty-one thousand, fifty-five".

Divisors: 1 3 5 15 14939 44817 74695 224085 585283 1755849 2926415 8779245 8743542737 26230628211 43717713685 131153141055