Base | Representation |
---|---|
bin | 10011000101011110100… |
… | …101111000001101011111 |
3 | 11122101100022111112011002 |
4 | 103011132211320031133 |
5 | 132442024303410101 |
6 | 2442304011220515 |
7 | 163520324112122 |
oct | 23053645701537 |
9 | 4571308445132 |
10 | 1311552013151 |
11 | 466253a126a6 |
12 | 19223014773b |
13 | 968a94b8693 |
14 | 4769d8b03b9 |
15 | 241b31a3d6b |
hex | 1315e97835f |
1311552013151 has 2 divisors, whose sum is σ = 1311552013152. Its totient is φ = 1311552013150.
The previous prime is 1311552013111. The next prime is 1311552013171. The reversal of 1311552013151 is 1513102551131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311552013151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311552013111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655776006575 + 655776006576.
It is an arithmetic number, because the mean of its divisors is an integer number (655776006576).
Almost surely, 21311552013151 is an apocalyptic number.
1311552013151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311552013151 is an equidigital number, since it uses as much as digits as its factorization.
1311552013151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2250, while the sum is 29.
Adding to 1311552013151 its reverse (1513102551131), we get a palindrome (2824654564282).
The spelling of 1311552013151 in words is "one trillion, three hundred eleven billion, five hundred fifty-two million, thirteen thousand, one hundred fifty-one".
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