Base | Representation |
---|---|
bin | 10011000101011111001… |
… | …000100111101110001111 |
3 | 11122101100221122020022001 |
4 | 103011133020213232033 |
5 | 132442034121330110 |
6 | 2442304534333131 |
7 | 163520464403452 |
oct | 23053710475617 |
9 | 4571327566261 |
10 | 1311561120655 |
11 | 466259073265 |
12 | 1922331ba1a7 |
13 | 968ab356c36 |
14 | 476a0ba1499 |
15 | 241b3da263a |
hex | 1315f227b8f |
1311561120655 has 8 divisors (see below), whose sum is σ = 1573895301984. Its totient is φ = 1049234258400.
The previous prime is 1311561120629. The next prime is 1311561120659. The reversal of 1311561120655 is 5560211651131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-1311561120655 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311561120659) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1427491 + ... + 2158900.
It is an arithmetic number, because the mean of its divisors is an integer number (196736912748).
Almost surely, 21311561120655 is an apocalyptic number.
1311561120655 is a deficient number, since it is larger than the sum of its proper divisors (262334181329).
1311561120655 is an equidigital number, since it uses as much as digits as its factorization.
1311561120655 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3659537.
The product of its (nonzero) digits is 27000, while the sum is 37.
Adding to 1311561120655 its reverse (5560211651131), we get a palindrome (6871772771786).
The spelling of 1311561120655 in words is "one trillion, three hundred eleven billion, five hundred sixty-one million, one hundred twenty thousand, six hundred fifty-five".
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