Base | Representation |
---|---|
bin | 10011000101100010011… |
… | …010100000010000101111 |
3 | 11122101111210011112002222 |
4 | 103011202122200100233 |
5 | 132442142212442320 |
6 | 2442314221505555 |
7 | 163522033145624 |
oct | 23054232402057 |
9 | 4571453145088 |
10 | 1311616140335 |
11 | 466287132376 |
12 | 1922497122bb |
13 | 968b987c067 |
14 | 476a820434b |
15 | 241b8b1e825 |
hex | 131626a042f |
1311616140335 has 8 divisors (see below), whose sum is σ = 1573950443760. Its totient is φ = 1049285528704.
The previous prime is 1311616140323. The next prime is 1311616140389. The reversal of 1311616140335 is 5330416161131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1311616140335 - 218 = 1311615878191 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1311616140295 and 1311616140304.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 69605 + ... + 1621134.
It is an arithmetic number, because the mean of its divisors is an integer number (196743805470).
Almost surely, 21311616140335 is an apocalyptic number.
1311616140335 is a deficient number, since it is larger than the sum of its proper divisors (262334303425).
1311616140335 is a wasteful number, since it uses less digits than its factorization.
1311616140335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1845897.
The product of its (nonzero) digits is 19440, while the sum is 35.
The spelling of 1311616140335 in words is "one trillion, three hundred eleven billion, six hundred sixteen million, one hundred forty thousand, three hundred thirty-five".
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