Base | Representation |
---|---|
bin | 1011111011100001000110… |
… | …1100100110001011001010 |
3 | 1201102222121010122220110120 |
4 | 2332320101230212023022 |
5 | 3204402334004302404 |
6 | 43521531443124110 |
7 | 2522452431032412 |
oct | 276702154461312 |
9 | 51388533586416 |
10 | 13117127025354 |
11 | 41a7a40274500 |
12 | 157a22b373636 |
13 | 741c2a8a4a91 |
14 | 334c2d98d642 |
15 | 17b3172da9d9 |
hex | bee11b262ca |
13117127025354 has 48 divisors (see below), whose sum is σ = 28837980321696. Its totient is φ = 3974613760480.
The previous prime is 13117127025283. The next prime is 13117127025371. The reversal of 13117127025354 is 45352072171131.
13117127025354 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10075312 + ... + 11302484.
It is an arithmetic number, because the mean of its divisors is an integer number (600791256702).
Almost surely, 213117127025354 is an apocalyptic number.
13117127025354 is an abundant number, since it is smaller than the sum of its proper divisors (15720853296342).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13117127025354 is a wasteful number, since it uses less digits than its factorization.
13117127025354 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1241923 (or 1241912 counting only the distinct ones).
The product of its (nonzero) digits is 176400, while the sum is 42.
Adding to 13117127025354 its reverse (45352072171131), we get a palindrome (58469199196485).
The spelling of 13117127025354 in words is "thirteen trillion, one hundred seventeen billion, one hundred twenty-seven million, twenty-five thousand, three hundred fifty-four".
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