Base | Representation |
---|---|
bin | 10011000101111001010… |
… | …011101000000010001110 |
3 | 11122102111112212102221110 |
4 | 103011321103220002032 |
5 | 132443434023310014 |
6 | 2442420301512450 |
7 | 163534405543452 |
oct | 23057123500216 |
9 | 4572445772843 |
10 | 1312000213134 |
11 | 466463a09a06 |
12 | 192336272726 |
13 | 9694b304c80 |
14 | 47703220662 |
15 | 241dc6d8d59 |
hex | 131794e808e |
1312000213134 has 32 divisors (see below), whose sum is σ = 2825905590144. Its totient is φ = 403683948000.
The previous prime is 1312000213129. The next prime is 1312000213189. The reversal of 1312000213134 is 4313120002131.
It is a super-2 number, since 2×13120002131342 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1312000213134.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4318677 + ... + 4612479.
It is an arithmetic number, because the mean of its divisors is an integer number (88309549692).
Almost surely, 21312000213134 is an apocalyptic number.
1312000213134 is an abundant number, since it is smaller than the sum of its proper divisors (1513905377010).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312000213134 is a wasteful number, since it uses less digits than its factorization.
1312000213134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 351072.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1312000213134 its reverse (4313120002131), we get a palindrome (5625120215265).
The spelling of 1312000213134 in words is "one trillion, three hundred twelve billion, two hundred thirteen thousand, one hundred thirty-four".
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