Base | Representation |
---|---|
bin | 1011111011101011110110… |
… | …1011000110001101100000 |
3 | 1201110021001012211201122021 |
4 | 2332322331223012031200 |
5 | 3204424241123012230 |
6 | 43523130032551224 |
7 | 2522614064420134 |
oct | 276727553061540 |
9 | 51407035751567 |
10 | 13120012313440 |
11 | 41a9190a0510a |
12 | 157a8b56b2514 |
13 | 74229a594336 |
14 | 335024c553c4 |
15 | 17b435770c7a |
hex | beebdac6360 |
13120012313440 has 24 divisors (see below), whose sum is σ = 30996029090880. Its totient is φ = 5248004925312.
The previous prime is 13120012313437. The next prime is 13120012313461. The reversal of 13120012313440 is 4431321002131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41000038320 + ... + 41000038639.
It is an arithmetic number, because the mean of its divisors is an integer number (1291501212120).
Almost surely, 213120012313440 is an apocalyptic number.
13120012313440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13120012313440 is an abundant number, since it is smaller than the sum of its proper divisors (17876016777440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13120012313440 is an equidigital number, since it uses as much as digits as its factorization.
13120012313440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82000076974 (or 82000076966 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13120012313440 its reverse (4431321002131), we get a palindrome (17551333315571).
The spelling of 13120012313440 in words is "thirteen trillion, one hundred twenty billion, twelve million, three hundred thirteen thousand, four hundred forty".
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