Base | Representation |
---|---|
bin | 111101000110000100… |
… | …1011101101101111101 |
3 | 110112122120112022120222 |
4 | 1322030021131231331 |
5 | 4122144234411031 |
6 | 140134513551125 |
7 | 12323160143555 |
oct | 1721411355575 |
9 | 415576468528 |
10 | 131200310141 |
11 | 5070717798a |
12 | 215168754a5 |
13 | c4ab777214 |
14 | 64c8a7a165 |
15 | 362d410e7b |
hex | 1e8c25db7d |
131200310141 has 2 divisors, whose sum is σ = 131200310142. Its totient is φ = 131200310140.
The previous prime is 131200310053. The next prime is 131200310147. The reversal of 131200310141 is 141013002131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130769747641 + 430562500 = 361621^2 + 20750^2 .
It is an emirp because it is prime and its reverse (141013002131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131200310141 - 222 = 131196115837 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131200310147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600155070 + 65600155071.
It is an arithmetic number, because the mean of its divisors is an integer number (65600155071).
Almost surely, 2131200310141 is an apocalyptic number.
It is an amenable number.
131200310141 is a deficient number, since it is larger than the sum of its proper divisors (1).
131200310141 is an equidigital number, since it uses as much as digits as its factorization.
131200310141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 131200310141 its reverse (141013002131), we get a palindrome (272213312272).
The spelling of 131200310141 in words is "one hundred thirty-one billion, two hundred million, three hundred ten thousand, one hundred forty-one".
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