Base | Representation |
---|---|
bin | 10011000101111010000… |
… | …001000011000010010011 |
3 | 11122102112101021101101022 |
4 | 103011322001003002103 |
5 | 132444000100321321 |
6 | 2442421405030055 |
7 | 163534612005122 |
oct | 23057201030223 |
9 | 4572471241338 |
10 | 1312012120211 |
11 | 46646a701971 |
12 | 19233a25532b |
13 | 96950913890 |
14 | 47704a3dab9 |
15 | 241dd78bdab |
hex | 1317a043093 |
1312012120211 has 4 divisors (see below), whose sum is σ = 1412936129472. Its totient is φ = 1211088110952.
The previous prime is 1312012120187. The next prime is 1312012120219. The reversal of 1312012120211 is 1120212102131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312012120211 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1312012120211.
It is not an unprimeable number, because it can be changed into a prime (1312012120219) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50462004611 + ... + 50462004636.
It is an arithmetic number, because the mean of its divisors is an integer number (353234032368).
Almost surely, 21312012120211 is an apocalyptic number.
1312012120211 is a deficient number, since it is larger than the sum of its proper divisors (100924009261).
1312012120211 is a wasteful number, since it uses less digits than its factorization.
1312012120211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100924009260.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1312012120211 its reverse (1120212102131), we get a palindrome (2432224222342).
The spelling of 1312012120211 in words is "one trillion, three hundred twelve billion, twelve million, one hundred twenty thousand, two hundred eleven".
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