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13120130402320 = 2451009162538781
BaseRepresentation
bin1011111011101100010010…
…1101100100100000010000
31201110021100110001021010111
42332323010231210200100
53204430011340333240
643523145452011104
72522620030231444
oct276730455444020
951407313037114
1013120130402320
1141a9241631027
12157a929160a94
137422b8b9c406
143350367d4824
1517b440cea1ea
hexbeec4b64810

13120130402320 has 40 divisors (see below), whose sum is σ = 30534535586520. Its totient is φ = 5242850887680.

The previous prime is 13120130402317. The next prime is 13120130402329. The reversal of 13120130402320 is 2320403102131.

It can be written as a sum of positive squares in 4 ways, for example, as 3422337201936 + 9697793200384 = 1849956^2 + 3114128^2 .

It is a tau number, because it is divible by the number of its divisors (40).

It is a super-2 number, since 2×131201304023202 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13120130402291 and 13120130402300.

It is not an unprimeable number, because it can be changed into a prime (13120130402329) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 81188671 + ... + 81350110.

It is an arithmetic number, because the mean of its divisors is an integer number (763363389663).

Almost surely, 213120130402320 is an apocalyptic number.

13120130402320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13120130402320 is an abundant number, since it is smaller than the sum of its proper divisors (17414405184200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13120130402320 is a wasteful number, since it uses less digits than its factorization.

13120130402320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 162539803 (or 162539797 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 13120130402320 its reverse (2320403102131), we get a palindrome (15440533504451).

The spelling of 13120130402320 in words is "thirteen trillion, one hundred twenty billion, one hundred thirty million, four hundred two thousand, three hundred twenty".

Divisors: 1 2 4 5 8 10 16 20 40 80 1009 2018 4036 5045 8072 10090 16144 20180 40360 80720 162538781 325077562 650155124 812693905 1300310248 1625387810 2600620496 3250775620 6501551240 13003102480 164001630029 328003260058 656006520116 820008150145 1312013040232 1640016300290 2624026080464 3280032600580 6560065201160 13120130402320