Base | Representation |
---|---|
bin | 11101110101001110110000… |
… | …001000111101111111011111 |
3 | 122012112201112122122212011001 |
4 | 131311032300020331333133 |
5 | 114144100301202210444 |
6 | 1143013015503011131 |
7 | 36430661021640346 |
oct | 3565166010757737 |
9 | 565481478585131 |
10 | 131201321131999 |
11 | 38894193405348 |
12 | 1286b840b99aa7 |
13 | 58293017965b1 |
14 | 245826bd48b5d |
15 | 1027caa24a8d4 |
hex | 7753b023dfdf |
131201321131999 has 4 divisors (see below), whose sum is σ = 131201916210720. Its totient is φ = 131200726053280.
The previous prime is 131201321131981. The next prime is 131201321132017. The reversal of 131201321131999 is 999131123102131.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (131201321131981) and next prime (131201321132017).
It is a cyclic number.
It is not a de Polignac number, because 131201321131999 - 25 = 131201321131967 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131201321111999) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 297208522 + ... + 297649639.
It is an arithmetic number, because the mean of its divisors is an integer number (32800479052680).
Almost surely, 2131201321131999 is an apocalyptic number.
131201321131999 is a deficient number, since it is larger than the sum of its proper divisors (595078721).
131201321131999 is an equidigital number, since it uses as much as digits as its factorization.
131201321131999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 595078720.
The product of its (nonzero) digits is 78732, while the sum is 46.
The spelling of 131201321131999 in words is "one hundred thirty-one trillion, two hundred one billion, three hundred twenty-one million, one hundred thirty-one thousand, nine hundred ninety-nine".
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