131201321434401 has 4 divisors (see below), whose sum is σ = 174935095245872. Its totient is φ = 87467547622932.

The previous prime is 131201321434397. The next prime is 131201321434481. The reversal of 131201321434401 is 104434123102131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 131201321434401 - 2² = 131201321434397 is a prime.

It is a super-2 number, since 2×131201321434401² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131201321434481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21866886905731 + ... + 21866886905736.

It is an arithmetic number, because the mean of its divisors is an integer number (43733773811468).

Almost surely, 2^{131201321434401} is an apocalyptic number.

It is an amenable number.

131201321434401 is a deficient number, since it is larger than the sum of its proper divisors (43733773811471).

131201321434401 is an equidigital number, since it uses as much as digits as its factorization.

131201321434401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43733773811470.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 131201321434401 its reverse (104434123102131), we get a palindrome (235635444536532).

The spelling of 131201321434401 in words is "one hundred thirty-one trillion, two hundred one billion, three hundred twenty-one million, four hundred thirty-four thousand, four hundred one".