Base | Representation |
---|---|
bin | 11101110101001110110111… |
… | …011010001111010101100000 |
3 | 122012112201212011011110210102 |
4 | 131311032313122033111200 |
5 | 114144101023413200000 |
6 | 1143013035541121532 |
7 | 36430664032436240 |
oct | 3565166732172540 |
9 | 565481764143712 |
10 | 131201443100000 |
11 | 38894246240749 |
12 | 1286b8759b92a8 |
13 | 5829320b2c200 |
14 | 2458280217b20 |
15 | 1027cb5cde3d5 |
hex | 7753b768f560 |
131201443100000 has 432 divisors, whose sum is σ = 399547229903136. Its totient is φ = 41523056640000.
The previous prime is 131201443099981. The next prime is 131201443100023. The reversal of 131201443100000 is 1344102131.
It is a super-2 number, since 2×1312014431000002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 117745472 + ... + 118854528.
It is an arithmetic number, because the mean of its divisors is an integer number (924877846998).
Almost surely, 2131201443100000 is an apocalyptic number.
131201443100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131201443100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (199773614951568).
131201443100000 is an abundant number, since it is smaller than the sum of its proper divisors (268345786803136).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131201443100000 is an equidigital number, since it uses as much as digits as its factorization.
131201443100000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1109125 (or 1109084 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 131201443100000 its reverse (1344102131), we get a palindrome (131202787202131).
The spelling of 131201443100000 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred forty-three million, one hundred thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •