Base | Representation |
---|---|
bin | 11101110101001111100101… |
… | …111101010011010110001000 |
3 | 122012112210212120122111202001 |
4 | 131311033211331103112020 |
5 | 114144104123323342100 |
6 | 1143013245235320344 |
7 | 36431022264363166 |
oct | 3565174575232610 |
9 | 565483776574661 |
10 | 131202224043400 |
11 | 38894607046014 |
12 | 1286ba534500b4 |
13 | 582941686c1b3 |
14 | 2458315c22236 |
15 | 1027d0e64ed6a |
hex | 7753e5f53588 |
131202224043400 has 48 divisors (see below), whose sum is σ = 305047072361700. Its totient is φ = 52480562484480.
The previous prime is 131202224043383. The next prime is 131202224043403. The reversal of 131202224043400 is 4340422202131.
It can be written as a sum of positive squares in 6 ways, for example, as 97089452146404 + 34112771896996 = 9853398^2 + 5840614^2 .
It is not an unprimeable number, because it can be changed into a prime (131202224043403) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 31492854 + ... + 35414746.
Almost surely, 2131202224043400 is an apocalyptic number.
131202224043400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131202224043400 is an abundant number, since it is smaller than the sum of its proper divisors (173844848318300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131202224043400 is a wasteful number, since it uses less digits than its factorization.
131202224043400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4089178 (or 4089169 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 131202224043400 its reverse (4340422202131), we get a palindrome (135542646245531).
The spelling of 131202224043400 in words is "one hundred thirty-one trillion, two hundred two billion, two hundred twenty-four million, forty-three thousand, four hundred".
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