1312101011321 has 4 divisors (see below), whose sum is σ = 1320790422144. Its totient is φ = 1303411600500.

The previous prime is 1312101011303. The next prime is 1312101011323. The reversal of 1312101011321 is 1231101012131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1312101011321 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1312101011321.

It is not an unprimeable number, because it can be changed into a prime (1312101011323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4344705185 + ... + 4344705486.

It is an arithmetic number, because the mean of its divisors is an integer number (330197605536).

Almost surely, 2^{1312101011321} is an apocalyptic number.

It is an amenable number.

1312101011321 is a deficient number, since it is larger than the sum of its proper divisors (8689410823).

1312101011321 is an equidigital number, since it uses as much as digits as its factorization.

1312101011321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8689410822.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1312101011321 its reverse (1231101012131), we get a palindrome (2543202023452).

The spelling of 1312101011321 in words is "one trillion, three hundred twelve billion, one hundred one million, eleven thousand, three hundred twenty-one".