Base | Representation |
---|---|
bin | 10011000101111111011… |
… | …001000110000110110000 |
3 | 11122102202122222111221201 |
4 | 103011333121012012300 |
5 | 132444141142412240 |
6 | 2442434350100544 |
7 | 163540055422054 |
oct | 23057731060660 |
9 | 4572678874851 |
10 | 1312102310320 |
11 | 46650660304a |
12 | 1923644aa754 |
13 | 969665011c9 |
14 | 477129d9c64 |
15 | 241e6654d9a |
hex | 1317f6461b0 |
1312102310320 has 40 divisors (see below), whose sum is σ = 3050839733760. Its totient is φ = 524806195200.
The previous prime is 1312102310317. The next prime is 1312102310339. The reversal of 1312102310320 is 230132012131.
It is a tau number, because it is divible by the number of its divisors (40).
It is a super-2 number, since 2×13121023103202 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 691345 + ... + 1761295.
It is an arithmetic number, because the mean of its divisors is an integer number (76270993344).
Almost surely, 21312102310320 is an apocalyptic number.
1312102310320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1312102310320 is an abundant number, since it is smaller than the sum of its proper divisors (1738737423440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312102310320 is a wasteful number, since it uses less digits than its factorization.
1312102310320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1085293 (or 1085287 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1312102310320 its reverse (230132012131), we get a palindrome (1542234322451).
The spelling of 1312102310320 in words is "one trillion, three hundred twelve billion, one hundred two million, three hundred ten thousand, three hundred twenty".
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