13121100020213 has 4 divisors (see below), whose sum is σ = 13121876387628. Its totient is φ = 13120323652800.

The previous prime is 13121100020209. The next prime is 13121100020333. The reversal of 13121100020213 is 31202000112131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8438368482769 + 4682731537444 = 2904887^2 + 2163962^2 .

It is a cyclic number.

It is not a de Polignac number, because 13121100020213 - 2² = 13121100020209 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13121100020191 and 13121100020200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13121100022213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 388158356 + ... + 388192157.

It is an arithmetic number, because the mean of its divisors is an integer number (3280469096907).

Almost surely, 2^{13121100020213} is an apocalyptic number.

It is an amenable number.

13121100020213 is a deficient number, since it is larger than the sum of its proper divisors (776367415).

13121100020213 is an equidigital number, since it uses as much as digits as its factorization.

13121100020213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 776367414.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13121100020213 its reverse (31202000112131), we get a palindrome (44323100132344).

The spelling of 13121100020213 in words is "thirteen trillion, one hundred twenty-one billion, one hundred million, twenty thousand, two hundred thirteen".