Base | Representation |
---|---|
bin | 11000011100001010… |
… | …00010100011100111 |
3 | 1020212102200011001122 |
4 | 30032011002203213 |
5 | 203333000312403 |
6 | 10005554444155 |
7 | 643103354552 |
oct | 141605024347 |
9 | 36772604048 |
10 | 13121104103 |
11 | 5623580798 |
12 | 266229365b |
13 | 13114c4333 |
14 | 8c6891699 |
15 | 51bdc4838 |
hex | 30e1428e7 |
13121104103 has 4 divisors (see below), whose sum is σ = 13123781880. Its totient is φ = 13118426328.
The previous prime is 13121104057. The next prime is 13121104111. The reversal of 13121104103 is 30140112131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30140112131 = 881 ⋅34211251.
It is a cyclic number.
It is not a de Polignac number, because 13121104103 - 26 = 13121104039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13121104133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1331525 + ... + 1341342.
It is an arithmetic number, because the mean of its divisors is an integer number (3280945470).
Almost surely, 213121104103 is an apocalyptic number.
13121104103 is a deficient number, since it is larger than the sum of its proper divisors (2677777).
13121104103 is an equidigital number, since it uses as much as digits as its factorization.
13121104103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2677776.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 13121104103 its reverse (30140112131), we get a palindrome (43261216234).
The spelling of 13121104103 in words is "thirteen billion, one hundred twenty-one million, one hundred four thousand, one hundred three".
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