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131211103320 = 233251146770951
BaseRepresentation
bin111101000110011001…
…0101000110001011000
3110112200022211200001100
41322030302220301120
54122210020301240
6140135541151400
712323350655553
oct1721462506130
9415608750040
10131211103320
1150712279a70
122151a3bb560
13c4b0a85b0b
1464ca28969a
15362e343e30
hex1e8cca8c58

131211103320 has 192 divisors, whose sum is σ = 466205725440. Its totient is φ = 31740192000.

The previous prime is 131211103313. The next prime is 131211103327. The reversal of 131211103320 is 23301112131.

131211103320 is a `hidden beast` number, since 1 + 31 + 211 + 103 + 320 = 666.

It is an interprime number because it is at equal distance from previous prime (131211103313) and next prime (131211103327).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 131211103293 and 131211103302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131211103327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1813845 + ... + 1884795.

It is an arithmetic number, because the mean of its divisors is an integer number (2428154820).

Almost surely, 2131211103320 is an apocalyptic number.

131211103320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131211103320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (233102862720).

131211103320 is an abundant number, since it is smaller than the sum of its proper divisors (334994622120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131211103320 is a wasteful number, since it uses less digits than its factorization.

131211103320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71446 (or 71439 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 131211103320 its reverse (23301112131), we get a palindrome (154512215451).

The spelling of 131211103320 in words is "one hundred thirty-one billion, two hundred eleven million, one hundred three thousand, three hundred twenty".