13121114003120 has 20 divisors (see below), whose sum is σ = 30506590057440. Its totient is φ = 5248445601216.

The previous prime is 13121114003113. The next prime is 13121114003131. The reversal of 13121114003120 is 2130041112131.

It is a tau number, because it is divible by the number of its divisors (20).

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13121114003092 and 13121114003101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82006962440 + ... + 82006962599.

It is an arithmetic number, because the mean of its divisors is an integer number (1525329502872).

Almost surely, 2^{13121114003120} is an apocalyptic number.

13121114003120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13121114003120 is an abundant number, since it is smaller than the sum of its proper divisors (17385476054320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121114003120 is a wasteful number, since it uses less digits than its factorization.

13121114003120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 164013925052 (or 164013925046 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13121114003120 its reverse (2130041112131), we get a palindrome (15251155115251).

The spelling of 13121114003120 in words is "thirteen trillion, one hundred twenty-one billion, one hundred fourteen million, three thousand, one hundred twenty".