Base | Representation |
---|---|
bin | 111101000110011001… |
… | …1100000100111000000 |
3 | 110112200100021021210011 |
4 | 1322030303200213000 |
5 | 4122210100111112 |
6 | 140135550114304 |
7 | 12323352630424 |
oct | 1721463404700 |
9 | 415610237704 |
10 | 131211332032 |
11 | 50712415890 |
12 | 2151a4ab994 |
13 | c4b0b35c51 |
14 | 64ca308b84 |
15 | 362e38baa7 |
hex | 1e8cce09c0 |
131211332032 has 28 divisors (see below), whose sum is σ = 284042714616. Its totient is φ = 59641514240.
The previous prime is 131211331991. The next prime is 131211332053. The reversal of 131211332032 is 230233112131.
It is a super-2 number, since 2×1312113320322 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a junction number, because it is equal to n+sod(n) for n = 131211331994 and 131211332012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93189163 + ... + 93190570.
Almost surely, 2131211332032 is an apocalyptic number.
It is an amenable number.
131211332032 is an abundant number, since it is smaller than the sum of its proper divisors (152831382584).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131211332032 is a wasteful number, since it uses less digits than its factorization.
131211332032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 186379756 (or 186379746 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 131211332032 its reverse (230233112131), we get a palindrome (361444444163).
The spelling of 131211332032 in words is "one hundred thirty-one billion, two hundred eleven million, three hundred thirty-two thousand, thirty-two".
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