Base | Representation |
---|---|
bin | 10011000110000000001… |
… | …110001101011110100110 |
3 | 11122102210122011220212010 |
4 | 103012000032031132212 |
5 | 132444203223443100 |
6 | 2442440004335050 |
7 | 163540314653241 |
oct | 23060016153646 |
9 | 4572718156763 |
10 | 1312116234150 |
11 | 466513453247 |
12 | 1923690a4486 |
13 | 96969367a67 |
14 | 477147c2258 |
15 | 241e79a5750 |
hex | 1318038d7a6 |
1312116234150 has 24 divisors (see below), whose sum is σ = 3254048261064. Its totient is φ = 349897662400.
The previous prime is 1312116234133. The next prime is 1312116234167. The reversal of 1312116234150 is 514326112131.
It is an interprime number because it is at equal distance from previous prime (1312116234133) and next prime (1312116234167).
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4373720631 + ... + 4373720930.
It is an arithmetic number, because the mean of its divisors is an integer number (135585344211).
Almost surely, 21312116234150 is an apocalyptic number.
1312116234150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1312116234150 is an abundant number, since it is smaller than the sum of its proper divisors (1941932026914).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312116234150 is a wasteful number, since it uses less digits than its factorization.
1312116234150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8747441576 (or 8747441571 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 30.
The spelling of 1312116234150 in words is "one trillion, three hundred twelve billion, one hundred sixteen million, two hundred thirty-four thousand, one hundred fifty".
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