Search a number
-
+
1312131132312 = 23371113371476149
BaseRepresentation
bin10011000110000001000…
…111000010101110011000
311122102211200012211021220
4103012001013002232120
5132444221032213222
62442441255532040
7163540555413150
oct23060107025630
94572750184256
101312131132312
114665208a9480
1219237208a020
139696c482c40
144771677d760
15241e8e49b5c
hex131811c2b98

1312131132312 has 256 divisors, whose sum is σ = 4523395968000. Its totient is φ = 306094049280.

The previous prime is 1312131132311. The next prime is 1312131132313. The reversal of 1312131132312 is 2132311312131.

It is an interprime number because it is at equal distance from previous prime (1312131132311) and next prime (1312131132313).

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a nude number because it is divisible by every one of its digits.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312131132311) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 150814 + ... + 1626962.

It is an arithmetic number, because the mean of its divisors is an integer number (17669515500).

Almost surely, 21312131132312 is an apocalyptic number.

1312131132312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1312131132312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2261697984000).

1312131132312 is an abundant number, since it is smaller than the sum of its proper divisors (3211264835688).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1312131132312 is a wasteful number, since it uses less digits than its factorization.

1312131132312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1476226 (or 1476222 counting only the distinct ones).

The product of its digits is 648, while the sum is 24.

Adding to 1312131132312 its reverse (2132311312131), we get a palindrome (3444442444443).

The spelling of 1312131132312 in words is "one trillion, three hundred twelve billion, one hundred thirty-one million, one hundred thirty-two thousand, three hundred twelve".