Base | Representation |
---|---|
bin | 11101110101011001110100… |
… | …010111001111100111011100 |
3 | 122012120212012201202120012110 |
4 | 131311121310113033213130 |
5 | 114144244120001040012 |
6 | 1143022302515434020 |
7 | 36431561331240255 |
oct | 3565316427174734 |
9 | 565525181676173 |
10 | 131213203143132 |
11 | 388992304a9160 |
12 | 12871bb82b5910 |
13 | 582a476359706 |
14 | 2458a78011b2c |
15 | 102825346173c |
hex | 7756745cf9dc |
131213203143132 has 24 divisors (see below), whose sum is σ = 333997244364672. Its totient is φ = 39761576710000.
The previous prime is 131213203143107. The next prime is 131213203143137. The reversal of 131213203143132 is 231341302312131.
It is a self number, because there is not a number n which added to its sum of digits gives 131213203143132.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131213203143137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 497019708744 + ... + 497019709007.
It is an arithmetic number, because the mean of its divisors is an integer number (13916551848528).
Almost surely, 2131213203143132 is an apocalyptic number.
131213203143132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
131213203143132 is an abundant number, since it is smaller than the sum of its proper divisors (202784041221540).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131213203143132 is a wasteful number, since it uses less digits than its factorization.
131213203143132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 994039417769 (or 994039417767 counting only the distinct ones).
The product of its (nonzero) digits is 7776, while the sum is 30.
Adding to 131213203143132 its reverse (231341302312131), we get a palindrome (362554505455263).
The spelling of 131213203143132 in words is "one hundred thirty-one trillion, two hundred thirteen billion, two hundred three million, one hundred forty-three thousand, one hundred thirty-two".
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