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1312132400000 = 275519172649
BaseRepresentation
bin10011000110000001001…
…011111000001110000000
311122102211202121020020022
4103012001023320032000
5132444221343300000
62442441343033012
7163540602243062
oct23060113701600
94572752536208
101312132400000
11466521594954
1219237259b768
139696c807c56
14477169cd732
15241e90ea585
hex131812f8380

1312132400000 has 192 divisors, whose sum is σ = 3439291590000. Its totient is φ = 497226240000.

The previous prime is 1312132399999. The next prime is 1312132400039. The reversal of 1312132400000 is 42312131.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7513676 + ... + 7686324.

Almost surely, 21312132400000 is an apocalyptic number.

1312132400000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1312132400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1719645795000).

1312132400000 is an abundant number, since it is smaller than the sum of its proper divisors (2127159190000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1312132400000 is an frugal number, since it uses more digits than its factorization.

1312132400000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 172707 (or 172675 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1312132400000 its reverse (42312131), we get a palindrome (1312174712131).

The spelling of 1312132400000 in words is "one trillion, three hundred twelve billion, one hundred thirty-two million, four hundred thousand".