13121404021423 has 2 divisors, whose sum is σ = 13121404021424. Its totient is φ = 13121404021422.

The previous prime is 13121404021421. The next prime is 13121404021441. The reversal of 13121404021423 is 32412040412131.

It is a happy number.

13121404021423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (32412040412131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13121404021423 - 2¹ = 13121404021421 is a prime.

Together with 13121404021421, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13121404021391 and 13121404021400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121404021421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560702010711 + 6560702010712.

It is an arithmetic number, because the mean of its divisors is an integer number (6560702010712).

Almost surely, 2^{13121404021423} is an apocalyptic number.

13121404021423 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121404021423 is an equidigital number, since it uses as much as digits as its factorization.

13121404021423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 13121404021423 its reverse (32412040412131), we get a palindrome (45533444433554).

The spelling of 13121404021423 in words is "thirteen trillion, one hundred twenty-one billion, four hundred four million, twenty-one thousand, four hundred twenty-three".