Base | Representation |
---|---|
bin | 111101000110101100… |
… | …0110110110001010011 |
3 | 110112201000200200021102 |
4 | 1322031120312301103 |
5 | 4122220101402011 |
6 | 140140540015015 |
7 | 12323532064121 |
oct | 1721530666123 |
9 | 415630620242 |
10 | 131221122131 |
11 | 507179a2280 |
12 | 2152183146b |
13 | c4b2b830c8 |
14 | 64cb736911 |
15 | 363017273b |
hex | 1e8d636c53 |
131221122131 has 32 divisors (see below), whose sum is σ = 153656455680. Its totient is φ = 110806272000.
The previous prime is 131221122127. The next prime is 131221122133.
131221122131 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 131221122131 - 22 = 131221122127 is a prime.
It is a super-2 number, since 2×1312211221312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131221122133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2144051 + ... + 2204403.
It is an arithmetic number, because the mean of its divisors is an integer number (4801764240).
Almost surely, 2131221122131 is an apocalyptic number.
131221122131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
131221122131 is a deficient number, since it is larger than the sum of its proper divisors (22435333549).
131221122131 is a wasteful number, since it uses less digits than its factorization.
131221122131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60587.
The product of its digits is 144, while the sum is 20.
It can be divided in two parts, 131221 and 122131, that added together give a palindrome (253352).
The spelling of 131221122131 in words is "one hundred thirty-one billion, two hundred twenty-one million, one hundred twenty-two thousand, one hundred thirty-one".
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