Base | Representation |
---|---|
bin | 111101000110101100… |
… | …0110110110001010100 |
3 | 110112201000200200021110 |
4 | 1322031120312301110 |
5 | 4122220101402012 |
6 | 140140540015020 |
7 | 12323532064122 |
oct | 1721530666124 |
9 | 415630620243 |
10 | 131221122132 |
11 | 507179a2281 |
12 | 21521831470 |
13 | c4b2b830c9 |
14 | 64cb736912 |
15 | 363017273c |
hex | 1e8d636c54 |
131221122132 has 12 divisors (see below), whose sum is σ = 306182618336. Its totient is φ = 43740374040.
The previous prime is 131221122127. The next prime is 131221122133. The reversal of 131221122132 is 231221122131.
It is a tau number, because it is divible by the number of its divisors (12).
It is a nude number because it is divisible by every one of its digits.
It is a junction number, because it is equal to n+sod(n) for n = 131221122099 and 131221122108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131221122133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5467546744 + ... + 5467546767.
Almost surely, 2131221122132 is an apocalyptic number.
131221122132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
131221122132 is an abundant number, since it is smaller than the sum of its proper divisors (174961496204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131221122132 is a wasteful number, since it uses less digits than its factorization.
131221122132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10935093518 (or 10935093516 counting only the distinct ones).
The product of its digits is 288, while the sum is 21.
Adding to 131221122132 its reverse (231221122131), we get a palindrome (362442244263).
Subtracting 131221122132 from its reverse (231221122131), we obtain a palindrome (99999999999).
The spelling of 131221122132 in words is "one hundred thirty-one billion, two hundred twenty-one million, one hundred twenty-two thousand, one hundred thirty-two".
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