Base | Representation |
---|---|
bin | 111101000110101100… |
… | …0110110110001010101 |
3 | 110112201000200200021111 |
4 | 1322031120312301111 |
5 | 4122220101402013 |
6 | 140140540015021 |
7 | 12323532064123 |
oct | 1721530666125 |
9 | 415630620244 |
10 | 131221122133 |
11 | 507179a2282 |
12 | 21521831471 |
13 | c4b2b830ca |
14 | 64cb736913 |
15 | 363017273d |
hex | 1e8d636c55 |
131221122133 has 2 divisors, whose sum is σ = 131221122134. Its totient is φ = 131221122132.
The previous prime is 131221122127. The next prime is 131221122139. The reversal of 131221122133 is 331221122131.
It is a balanced prime because it is at equal distance from previous prime (131221122127) and next prime (131221122139).
It can be written as a sum of positive squares in only one way, i.e., 82655100004 + 48566022129 = 287498^2 + 220377^2 .
It is a cyclic number.
It is not a de Polignac number, because 131221122133 - 29 = 131221121621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131221122139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65610561066 + 65610561067.
It is an arithmetic number, because the mean of its divisors is an integer number (65610561067).
Almost surely, 2131221122133 is an apocalyptic number.
It is an amenable number.
131221122133 is a deficient number, since it is larger than the sum of its proper divisors (1).
131221122133 is an equidigital number, since it uses as much as digits as its factorization.
131221122133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 432, while the sum is 22.
Adding to 131221122133 its reverse (331221122131), we get a palindrome (462442244264).
The spelling of 131221122133 in words is "one hundred thirty-one billion, two hundred twenty-one million, one hundred twenty-two thousand, one hundred thirty-three".
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