Base | Representation |
---|---|
bin | 1011111011110100000010… |
… | …1111001100010100010001 |
3 | 1201110110201110102212010012 |
4 | 2332331000233030110101 |
5 | 3204443242031433241 |
6 | 43524132142444305 |
7 | 2523022424600654 |
oct | 276750057142421 |
9 | 51413643385105 |
10 | 13122211202321 |
11 | 41aa10a145951 |
12 | 157b209b93695 |
13 | 74255acc7010 |
14 | 335192cc389b |
15 | 17b51381d6eb |
hex | bef40bcc511 |
13122211202321 has 64 divisors (see below), whose sum is σ = 15072112742400. Its totient is φ = 11324726899200.
The previous prime is 13122211202293. The next prime is 13122211202341. The reversal of 13122211202321 is 12320211222131.
13122211202321 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a de Polignac number, because none of the positive numbers 2k-13122211202321 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13122211202341) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4847509250 + ... + 4847511956.
It is an arithmetic number, because the mean of its divisors is an integer number (235501761600).
Almost surely, 213122211202321 is an apocalyptic number.
It is an amenable number.
13122211202321 is a deficient number, since it is larger than the sum of its proper divisors (1949901540079).
13122211202321 is a wasteful number, since it uses less digits than its factorization.
13122211202321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3670.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 13122211202321 its reverse (12320211222131), we get a palindrome (25442422424452).
The spelling of 13122211202321 in words is "thirteen trillion, one hundred twenty-two billion, two hundred eleven million, two hundred two thousand, three hundred twenty-one".
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