Base | Representation |
---|---|
bin | 1011111011110100000111… |
… | …0111010100101101111101 |
3 | 1201110110202210000112002101 |
4 | 2332331001313110231331 |
5 | 3204443311402023401 |
6 | 43524134100025101 |
7 | 2523023044403416 |
oct | 276750167245575 |
9 | 51413683015071 |
10 | 13122230111101 |
11 | 41aa119890341 |
12 | 157b214392191 |
13 | 742561bb7847 |
14 | 33519560680d |
15 | 17b515306101 |
hex | bef41dd4b7d |
13122230111101 has 2 divisors, whose sum is σ = 13122230111102. Its totient is φ = 13122230111100.
The previous prime is 13122230111041. The next prime is 13122230111161. The reversal of 13122230111101 is 10111103222131.
It is a balanced prime because it is at equal distance from previous prime (13122230111041) and next prime (13122230111161).
It can be written as a sum of positive squares in only one way, i.e., 10497016808100 + 2625213303001 = 3239910^2 + 1620251^2 .
It is a cyclic number.
It is not a de Polignac number, because 13122230111101 - 233 = 13113640176509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122230111161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561115055550 + 6561115055551.
It is an arithmetic number, because the mean of its divisors is an integer number (6561115055551).
Almost surely, 213122230111101 is an apocalyptic number.
It is an amenable number.
13122230111101 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122230111101 is an equidigital number, since it uses as much as digits as its factorization.
13122230111101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 13122230111101 its reverse (10111103222131), we get a palindrome (23233333333232).
The spelling of 13122230111101 in words is "thirteen trillion, one hundred twenty-two billion, two hundred thirty million, one hundred eleven thousand, one hundred one".
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