Base | Representation |
---|---|
bin | 10011000110000111000… |
… | …000010110111101101100 |
3 | 11122110002120100000221020 |
4 | 103012013000112331230 |
5 | 132444421342343000 |
6 | 2442455151534140 |
7 | 163543166222025 |
oct | 23060700267554 |
9 | 4573076300836 |
10 | 1312230043500 |
11 | 466571716962 |
12 | 19239b22a350 |
13 | 96986b04c7c |
14 | 47725969c4c |
15 | 24202986ba0 |
hex | 13187016f6c |
1312230043500 has 48 divisors (see below), whose sum is σ = 3821213891040. Its totient is φ = 349928011200.
The previous prime is 1312230043499. The next prime is 1312230043513. The reversal of 1312230043500 is 53400322131.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 437408515 + ... + 437411514.
It is an arithmetic number, because the mean of its divisors is an integer number (79608622730).
Almost surely, 21312230043500 is an apocalyptic number.
1312230043500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1312230043500 is an abundant number, since it is smaller than the sum of its proper divisors (2508983847540).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312230043500 is a wasteful number, since it uses less digits than its factorization.
1312230043500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 874820051 (or 874820039 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 24.
Adding to 1312230043500 its reverse (53400322131), we get a palindrome (1365630365631).
The spelling of 1312230043500 in words is "one trillion, three hundred twelve billion, two hundred thirty million, forty-three thousand, five hundred".
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