Base | Representation |
---|---|
bin | 1011111011110100100010… |
… | …0011101100010110101000 |
3 | 1201110111001121022200002211 |
4 | 2332331020203230112220 |
5 | 3204444024123434134 |
6 | 43524153150534504 |
7 | 2523025610032441 |
oct | 276751043542650 |
9 | 51414047280084 |
10 | 13122342405544 |
11 | 41aa177209869 |
12 | 157b245b07434 |
13 | 74257c244368 |
14 | 3351a64b82c8 |
15 | 17b5200d8764 |
hex | bef488ec5a8 |
13122342405544 has 64 divisors (see below), whose sum is σ = 26251297309440. Its totient is φ = 6136054172160.
The previous prime is 13122342405539. The next prime is 13122342405553. The reversal of 13122342405544 is 44550424322131.
It is a junction number, because it is equal to n+sod(n) for n = 13122342405497 and 13122342405506.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1625989 + ... + 5374804.
It is an arithmetic number, because the mean of its divisors is an integer number (410176520460).
Almost surely, 213122342405544 is an apocalyptic number.
It is an amenable number.
13122342405544 is an abundant number, since it is smaller than the sum of its proper divisors (13128954903896).
13122342405544 is a wasteful number, since it uses less digits than its factorization.
13122342405544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7001050 (or 7001046 counting only the distinct ones).
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 13122342405544 its reverse (44550424322131), we get a palindrome (57672766727675).
The spelling of 13122342405544 in words is "thirteen trillion, one hundred twenty-two billion, three hundred forty-two million, four hundred five thousand, five hundred forty-four".
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