Base | Representation |
---|---|
bin | 10011000110000111101… |
… | …010100111111100100111 |
3 | 11122110010100011221022012 |
4 | 103012013222213330213 |
5 | 132444432211414421 |
6 | 2442500225224435 |
7 | 163543362336062 |
oct | 23060752477447 |
9 | 4573110157265 |
10 | 1312241123111 |
11 | 4665779a4166 |
12 | 1923a2a9211b |
13 | 969891b4059 |
14 | 477272118d9 |
15 | 2420392495b |
hex | 13187aa7f27 |
1312241123111 has 4 divisors (see below), whose sum is σ = 1381306445400. Its totient is φ = 1243175800824.
The previous prime is 1312241123059. The next prime is 1312241123153. The reversal of 1312241123111 is 1113211422131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312241123111 - 214 = 1312241106727 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312241123161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34532661116 + ... + 34532661153.
It is an arithmetic number, because the mean of its divisors is an integer number (345326611350).
Almost surely, 21312241123111 is an apocalyptic number.
1312241123111 is a deficient number, since it is larger than the sum of its proper divisors (69065322289).
1312241123111 is an equidigital number, since it uses as much as digits as its factorization.
1312241123111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69065322288.
The product of its digits is 288, while the sum is 23.
Adding to 1312241123111 its reverse (1113211422131), we get a palindrome (2425452545242).
The spelling of 1312241123111 in words is "one trillion, three hundred twelve billion, two hundred forty-one million, one hundred twenty-three thousand, one hundred eleven".
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