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13122420215310 = 2335721317175307
BaseRepresentation
bin1011111011110100110100…
…1100100000111000001110
31201110111021000201211001000
42332331031030200320032
53204444204033342220
643524205010401130
72523030543304200
oct276751514407016
951414230654030
1013122420215310
1141aa20712445a
12157b267b901a6
137425923b8843
143351b2970770
1517b526d58390
hexbef4d320e0e

13122420215310 has 192 divisors, whose sum is σ = 40709914295040. Its totient is φ = 2999142780480.

The previous prime is 13122420215309. The next prime is 13122420215369. The reversal of 13122420215310 is 1351202422131.

It is a happy number.

13122420215310 is a `hidden beast` number, since 1 + 3 + 1 + 22 + 420 + 215 + 3 + 1 + 0 = 666.

It is a super-2 number, since 2×131224202153102 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 174214677 + ... + 174289983.

It is an arithmetic number, because the mean of its divisors is an integer number (212030803620).

Almost surely, 213122420215310 is an apocalyptic number.

13122420215310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 13122420215310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20354957147520).

13122420215310 is an abundant number, since it is smaller than the sum of its proper divisors (27587494079730).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13122420215310 is a wasteful number, since it uses less digits than its factorization.

13122420215310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 88508 (or 88495 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 13122420215310 its reverse (1351202422131), we get a palindrome (14473622637441).

The spelling of 13122420215310 in words is "thirteen trillion, one hundred twenty-two billion, four hundred twenty million, two hundred fifteen thousand, three hundred ten".