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1312303103100 = 223252111271043747
BaseRepresentation
bin10011000110001011010…
…111000011110001111100
311122110021122210211212100
4103012023113003301330
5133000044043244400
62442510321505100
7163545044220543
oct23061327036174
94573248724770
101312303103100
114665a99876a0
121923bb7a2190
1396998ca52c2
144773154715a
15242090b9100
hex1318b5c3c7c

1312303103100 has 216 divisors, whose sum is σ = 4522618533888. Its totient is φ = 315628790400.

The previous prime is 1312303103017. The next prime is 1312303103107. The reversal of 1312303103100 is 13013032131.

It is a happy number.

1312303103100 is a `hidden beast` number, since 1 + 3 + 12 + 30 + 310 + 310 + 0 = 666.

It is a super-2 number, since 2×13123031031002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312303103107) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 735427 + ... + 1779173.

It is an arithmetic number, because the mean of its divisors is an integer number (20938048768).

Almost surely, 21312303103100 is an apocalyptic number.

1312303103100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1312303103100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2261309266944).

1312303103100 is an abundant number, since it is smaller than the sum of its proper divisors (3210315430788).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1312303103100 is a wasteful number, since it uses less digits than its factorization.

1312303103100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1043905 (or 1043895 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 18.

Adding to 1312303103100 its reverse (13013032131), we get a palindrome (1325316135231).

It can be divided in two parts, 1312303 and 103100, that added together give a triangular number (1415403 = T1682).

The spelling of 1312303103100 in words is "one trillion, three hundred twelve billion, three hundred three million, one hundred three thousand, one hundred".