Search a number
-
+
131233401331340 = 2257111761712911527
BaseRepresentation
bin11101110101101100101000…
…010001001101111010001100
3122012122210100101012211120012
4131311230220101031322030
5114200112001220100330
61143035443045012352
736433205011064330
oct3565545021157214
9565583311184505
10131233401331340
11388a6855892990
1212875ab46b40b8
13582c344b05a79
142459a327677c0
151028a367c9c95
hex775b2844de8c

131233401331340 has 384 divisors, whose sum is σ = 369852207943680. Its totient is φ = 37858096742400.

The previous prime is 131233401331303. The next prime is 131233401331343. The reversal of 131233401331340 is 43133104332131.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 131233401331297 and 131233401331306.

It is not an unprimeable number, because it can be changed into a prime (131233401331343) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 11384864657 + ... + 11384876183.

It is an arithmetic number, because the mean of its divisors is an integer number (963156791520).

Almost surely, 2131233401331340 is an apocalyptic number.

131233401331340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131233401331340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (184926103971840).

131233401331340 is an abundant number, since it is smaller than the sum of its proper divisors (238618806612340).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131233401331340 is a wasteful number, since it uses less digits than its factorization.

131233401331340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18761 (or 18759 counting only the distinct ones).

The product of its (nonzero) digits is 23328, while the sum is 32.

Adding to 131233401331340 its reverse (43133104332131), we get a palindrome (174366505663471).

The spelling of 131233401331340 in words is "one hundred thirty-one trillion, two hundred thirty-three billion, four hundred one million, three hundred thirty-one thousand, three hundred forty".