Base | Representation |
---|---|
bin | 1011111011111011100010… |
… | …1101110101100101101000 |
3 | 1201110122220202002022110120 |
4 | 2332332320231311211220 |
5 | 3210011402333104000 |
6 | 43525104010243240 |
7 | 2523123336214140 |
oct | 276767055654550 |
9 | 51418822068416 |
10 | 13124224113000 |
11 | 41aaa524004a0 |
12 | 157b690126520 |
13 | 7427bc041a20 |
14 | 33530437d920 |
15 | 17b5d03d16a0 |
hex | befb8b75968 |
13124224113000 has 1024 divisors, whose sum is σ = 55524193320960. Its totient is φ = 2492352000000.
The previous prime is 13124224112999. The next prime is 13124224113047. The reversal of 13124224113000 is 31142242131.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 303281365 + ... + 303324635.
It is an arithmetic number, because the mean of its divisors is an integer number (54222845040).
Almost surely, 213124224113000 is an apocalyptic number.
13124224113000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13124224113000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27762096660480).
13124224113000 is an abundant number, since it is smaller than the sum of its proper divisors (42399969207960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13124224113000 is a wasteful number, since it uses less digits than its factorization.
13124224113000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43427 (or 43413 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13124224113000 its reverse (31142242131), we get a palindrome (13155366355131).
It can be divided in two parts, 131242 and 24113000, that added together give a palindrome (24244242).
The spelling of 13124224113000 in words is "thirteen trillion, one hundred twenty-four billion, two hundred twenty-four million, one hundred thirteen thousand".
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