1312433232440 has 384 divisors, whose sum is σ = 3471474283200. Its totient is φ = 445412352000.

The previous prime is 1312433232371. The next prime is 1312433232533. The reversal of 1312433232440 is 442323342131.

It is a super-2 number, since 2×1312433232440² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1312433232397 and 1312433232406.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 609582404 + ... + 609584556.

Almost surely, 2^{1312433232440} is an apocalyptic number.

1312433232440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1312433232440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1735737141600).

1312433232440 is an abundant number, since it is smaller than the sum of its proper divisors (2159041050760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1312433232440 is a wasteful number, since it uses less digits than its factorization.

1312433232440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2359 (or 2344 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 1312433232440 its reverse (442323342131), we get a palindrome (1754756574571).

The spelling of 1312433232440 in words is "one trillion, three hundred twelve billion, four hundred thirty-three million, two hundred thirty-two thousand, four hundred forty".