13124341403 has 4 divisors (see below), whose sum is σ = 13125178128. Its totient is φ = 13123504680.

The previous prime is 13124341393. The next prime is 13124341423. The reversal of 13124341403 is 30414342131.

It is a happy number.

13124341403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13124341403 - 2⁴ = 13124341387 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13124341423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 394376 + ... + 426357.

It is an arithmetic number, because the mean of its divisors is an integer number (3281294532).

Almost surely, 2^13124341403 is an apocalyptic number.

13124341403 is a deficient number, since it is larger than the sum of its proper divisors (836725).

13124341403 is an equidigital number, since it uses as much as digits as its factorization.

13124341403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 836724.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 13124341403 its reverse (30414342131), we get a palindrome (43538683534).

The spelling of 13124341403 in words is "thirteen billion, one hundred twenty-four million, three hundred forty-one thousand, four hundred three".