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13124341423 is a prime number
BaseRepresentation
bin11000011100100010…
…11000111010101111
31020212122202121211101
430032101120322233
5203334312411143
610010152103531
7643143030034
oct141621307257
936778677741
1013124341423
115625391a66
122663394ba7
1313120889cb
148c709538b
1551c313b4d
hex30e458eaf

13124341423 has 2 divisors, whose sum is σ = 13124341424. Its totient is φ = 13124341422.

The previous prime is 13124341393. The next prime is 13124341453. The reversal of 13124341423 is 32414342131.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (13124341393) and next prime (13124341453).

It is an emirp because it is prime and its reverse (32414342131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13124341423 - 233 = 4534406831 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13124341391 and 13124341400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13124341453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562170711 + 6562170712.

It is an arithmetic number, because the mean of its divisors is an integer number (6562170712).

Almost surely, 213124341423 is an apocalyptic number.

13124341423 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124341423 is an equidigital number, since it uses as much as digits as its factorization.

13124341423 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6912, while the sum is 28.

Adding to 13124341423 its reverse (32414342131), we get a palindrome (45538683554).

The spelling of 13124341423 in words is "thirteen billion, one hundred twenty-four million, three hundred forty-one thousand, four hundred twenty-three".