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1312452211103 = 11119313837373
BaseRepresentation
bin10011000110010100001…
…111110111000110011111
311122110200001101022120222
4103012110033313012133
5133000400231223403
62442533205431555
7163551534504005
oct23062417670637
94573601338528
101312452211103
1146667606a750
1219244170b5bb
13969c0b511a7
144774727ca75
152421721e338
hex131943f719f

1312452211103 has 4 divisors (see below), whose sum is σ = 1431766048488. Its totient is φ = 1193138373720.

The previous prime is 1312452211093. The next prime is 1312452211111. The reversal of 1312452211103 is 3011122542131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312452211103 - 210 = 1312452210079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312452211123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59656918676 + ... + 59656918697.

It is an arithmetic number, because the mean of its divisors is an integer number (357941512122).

Almost surely, 21312452211103 is an apocalyptic number.

1312452211103 is a deficient number, since it is larger than the sum of its proper divisors (119313837385).

1312452211103 is a wasteful number, since it uses less digits than its factorization.

1312452211103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119313837384.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 1312452211103 its reverse (3011122542131), we get a palindrome (4323574753234).

The spelling of 1312452211103 in words is "one trillion, three hundred twelve billion, four hundred fifty-two million, two hundred eleven thousand, one hundred three".

Divisors: 1 11 119313837373 1312452211103