Base | Representation |
---|---|
bin | 11101110101111110000100… |
… | …001000100001000011101111 |
3 | 122012201120200002020212010012 |
4 | 131311332010020201003233 |
5 | 114200413321320023120 |
6 | 1143052220451003435 |
7 | 36434436643536131 |
oct | 3565760410410357 |
9 | 565646602225105 |
10 | 131252122423535 |
11 | 38903792410603 |
12 | 1287965a29957b |
13 | 583103954c009 |
14 | 245a8cac5d051 |
15 | 10292801201c5 |
hex | 775f842210ef |
131252122423535 has 8 divisors (see below), whose sum is σ = 159720892639776. Its totient is φ = 103522800784480.
The previous prime is 131252122423511. The next prime is 131252122423561. The reversal of 131252122423535 is 535324221252131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 131252122423535 - 222 = 131252118229231 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131252122423492 and 131252122423501.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 184862143904 + ... + 184862144613.
It is an arithmetic number, because the mean of its divisors is an integer number (19965111579972).
Almost surely, 2131252122423535 is an apocalyptic number.
131252122423535 is a deficient number, since it is larger than the sum of its proper divisors (28468770216241).
131252122423535 is an equidigital number, since it uses as much as digits as its factorization.
131252122423535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 369724288593.
The product of its digits is 432000, while the sum is 41.
Adding to 131252122423535 its reverse (535324221252131), we get a palindrome (666576343675666).
The spelling of 131252122423535 in words is "one hundred thirty-one trillion, two hundred fifty-two billion, one hundred twenty-two million, four hundred twenty-three thousand, five hundred thirty-five".
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