Base | Representation |
---|---|
bin | 11000011100101001… |
… | …10100010011110111 |
3 | 1020212201110021112001 |
4 | 30032110310103313 |
5 | 203340030140210 |
6 | 10010223240131 |
7 | 643153461664 |
oct | 141624642367 |
9 | 36781407461 |
10 | 13125240055 |
11 | 5625946134 |
12 | 2663749047 |
13 | 1312311a45 |
14 | 8c724aa6b |
15 | 51c44003a |
hex | 30e5344f7 |
13125240055 has 4 divisors (see below), whose sum is σ = 15750288072. Its totient is φ = 10500192040.
The previous prime is 13125240047. The next prime is 13125240091. The reversal of 13125240055 is 55004252131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55004252131 = 17 ⋅3235544243.
It is not a de Polignac number, because 13125240055 - 23 = 13125240047 is a prime.
It is a super-3 number, since 3×131252400553 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1312524001 + ... + 1312524010.
It is an arithmetic number, because the mean of its divisors is an integer number (3937572018).
Almost surely, 213125240055 is an apocalyptic number.
13125240055 is a deficient number, since it is larger than the sum of its proper divisors (2625048017).
13125240055 is an equidigital number, since it uses as much as digits as its factorization.
13125240055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2625048016.
The product of its (nonzero) digits is 6000, while the sum is 28.
Adding to 13125240055 its reverse (55004252131), we get a palindrome (68129492186).
The spelling of 13125240055 in words is "thirteen billion, one hundred twenty-five million, two hundred forty thousand, fifty-five".
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